-4-3m+3m^2=-m^2-10m+3

Solution for -4-3m+3m^2=-m^2-10m+3 equation:

-4-3m+3m^2=-m^2-10m+3

We move all terms to the left:

-4-3m+3m^2-(-m^2-10m+3)=0

We get rid of parentheses

3m^2+m^2+10m-3m-3-4=0

We add all the numbers together, and all the variables

4m^2+7m-7=0

a = 4; b = 7; c = -7;
Δ = b2-4ac
Δ = 72-4·4·(-7)
Δ = 161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{161}}{2*4}=\frac{-7-\sqrt{161}}{8}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{161}}{2*4}=\frac{-7+\sqrt{161}}{8}
$